Solving a Circuit with Diodes: Find V Across Resistor

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SUMMARY

This discussion focuses on solving a circuit with diodes to find the voltage (V) across a resistor. The participants emphasize that both diodes in the circuit are forward biased, which allows them to be replaced with short circuits or voltage sources of 0.6 V, depending on whether they are ideal or not. A recommended approach is to first ignore the diodes and calculate the resistor divider voltages separately, then analyze the impact of adding each diode one at a time. The complexity arises from the interdependence of diode states, which affects the overall circuit behavior.

PREREQUISITES
  • Understanding of diode behavior in circuits
  • Knowledge of resistor divider circuits
  • Familiarity with ideal vs. non-ideal diode models
  • Basic circuit analysis techniques
NEXT STEPS
  • Study the principles of diode forward biasing and its effects on circuit analysis
  • Learn about resistor divider circuits and their applications in voltage calculations
  • Explore the differences between ideal and non-ideal diodes in circuit simulations
  • Investigate circuit analysis methods for multiple diodes, including iterative approaches
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing diode circuits and voltage calculations.

Ry122
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Homework Statement




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Homework Equations





The Attempt at a Solution


I'm unsure where to begin with this.
I need to find the value V across the resistor and I'm unsure how.
What effect do the diodes have in a circuit that's set up in this way?
 
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Both diodes are forward biased.
If they are ideal, you can replace them with short circuits. If not, you can replace them by voltage sources of 0.6 V.
 
Ry122 said:

Homework Statement




http://img832.imageshack.us/img832/6302/20285200.jpg

Uploaded with ImageShack.us

Homework Equations





The Attempt at a Solution


I'm unsure where to begin with this.
I need to find the value V across the resistor and I'm unsure how.
What effect do the diodes have in a circuit that's set up in this way?

Start by ignoring the diodes, and solve for the two separate resistor divider voltages. What do you get? Now if you put in one diode at a time, what happens? And then with both of them in at once?

CEL said:
Both diodes are forward biased.

I'm not sure that is true...
 
Last edited by a moderator:
How come when solving these circuits you're supposed to make assumptions about which ones might be on and which ones are off, and then check to see if you're right?

Why can't you just look at the voltages on either side of the diodes and see whether the cathode or anode side is greater?
 
Ry122 said:
Why can't you just look at the voltages on either side of the diodes and see whether the cathode or anode side is greater?

You can if there's just one diode, but in general the A-K polarity of a particular diode will depend on the state (conducting / non conducting) of all the other diodes in the circuit. Your original question above is a good example of this.
 

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