Solving a Double Integral: Int[1 to 2] Int[0 to x] of 1/(sqrt((x^2)+(y^2)))dydx

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SUMMARY

The discussion focuses on solving the double integral defined as Int[1 to 2] Int[0 to x] of 1/(sqrt((x^2)+(y^2)))dydx. The initial approach involves rewriting the integrand by raising the denominator to the -1/2 power and considering substitution methods. A key suggestion is to first evaluate the inner integral, which simplifies to ∫[0 to x] (1/sqrt(x^2+y^2)) dy, where x is treated as a constant. The recommended technique for solving this integral is to apply a trigonometric substitution, specifically using y/x = tan(θ).

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Homework Statement


Howdy fellas, long time lurker, first time poster. If someone could get me started on the right track for this problem, it would be appreciated.

Also, I'm not sure how to write equations yet, but I'll do my best to explain the problem clearly

Homework Equations



Int[1 to 2] Int[0 to x] of 1/(sqrt((x^2)+(y^2)))dydx

The Attempt at a Solution



As I said, not sure how to get started. My gut was telling me to raise the denominator to the -1/2 power and use the substitution rule? But I'm not sure.

Thanks
 
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Hi FecalFrown! :smile:

Let's start with the inner integral, this is

[tex]\int_0^x{\frac{1}{\sqrt{x^2+y^2}}dy}[/tex]

where x is simply a constant. The trick is to factor x out of the square root, and then to do a trigonometric substitution [itex]\frac{y}{x}=\tan(\theta)[/itex]
 

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