Solving a Frictionless Pulley Problem: Acceleration of m2

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physicsbro
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Homework Statement


A 29.3 kg block, m1, is on a horizontal surface, connected to a 6.70 kg block, m2, by a massless string as shown. The frictionless pulley has a radius R = 0.055 m and a moment of inertia I = 0.100 kg·m2. A force F = 202.5 N acts on m1 at an angle θ = 29.7°. There is no friction between m1 and the surface. What is the upward acceleration of m2?

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Homework Equations





The Attempt at a Solution



My textbook says that the net tension divided by the moment of inertia would give me the [tex]\alpha[/tex] and that multiplied by the radius would give me the acceleration, but it didnt work.
 
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physicsbro said:
My textbook says that the net tension divided by the moment of inertia would give me the [tex]\alpha[/tex] and that multiplied by the radius would give me the acceleration, but it didnt work.
That's certainly true, but you'll need the tensions to make use of it. Hint: Apply Newton's 2nd law to both masses and the pulley. Combine those three equations and you can solve for the acceleration.