Solving a Higher-Order PDE: Traveling Wave & Phase Portrait

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SUMMARY

The discussion focuses on solving the higher-order partial differential equation (PDE) ut + 6u³ux + uxxx = 0, which is a variant of the Korteweg-de Vries (KdV) equation. Participants derive a third-order ordinary differential equation (ODE) by assuming a traveling wave solution u = f(x-ct) and subsequently reduce the order of this ODE to express g(f) as (f')²/2 = -f⁵/4 + cf²/6 + A1f + A2. The phase portrait for real solutions is sketched based on the polynomial g(f), which is determined to have five real roots.

PREREQUISITES
  • Understanding of partial differential equations (PDEs)
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of phase portraits and their significance in dynamical systems
  • Proficiency in polynomial functions and their roots
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  • Study the derivation of traveling wave solutions for PDEs
  • Learn about the Korteweg-de Vries (KdV) equation and its applications
  • Explore methods for sketching phase portraits for higher-order ODEs
  • Investigate the implications of real roots in polynomial functions on system dynamics
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Mathematicians, physicists, and engineers working with nonlinear dynamics, particularly those interested in the analysis of higher-order PDEs and their traveling wave solutions.

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Homework Statement


Consider the PDE ut + 6u3ux + uxxx = 0
which may be thought of as a higher-order variant of the KdV.
a) Assume a traveling wave u = f(x-ct) and derive the 3rd-order ODE for that solution.
b) Reduce the order of this ODE and obtain the expression for the polynomial g(f), where g(f) = (f')2/2
c) Sketch the (f,f') phase portrait for real solutions, assuming that g(f) has the maximum number of real roots.

Homework Equations





The Attempt at a Solution


a) I let u = f(x-ct) and got -cf'(x-ct) + 6f(x-ct)3f'(x-ct) + f'''(x-ct) = 0, is this the 3rd-order ODE required.
b) I got (f')2/2 = g(f) where g(f) = -f(x-ct)5/4 + cf(x-ct)2/6 + A1f(x-ct) + A2
c) I know that this has 5 solutions (5th-order polynomial), do I write it in the form (f')2/2 = g(f) = 1/4*(f-F1)(f-F2)(f-F3)(f-F4)(F5-f) and if so how does this look on phase portrait.
 
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I just need to do c). Any ideas?
 

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