Solving D'alembert Equation for Wave eq. u(4,1) & u(1,4)

[ajax2000]

Homework Statement

For a wave equation, utt-uxx=0, 0<x< ∞
u(0,t)=t^2, t>0
u(x,0)=x^2, 0<x< ∞
ut(x,0)=6x, 0<x< ∞

evaulate u(4,1) and u(1,4)

uxx is taking 2 derivatives in respective of x

Homework Equations

D'alembert's equation u=(f(x+ct)+f(x-ct))/2 + (1/ct)(∫g(s)ds

The Attempt at a Solution

this seems easy, just plug everything into the formula to get u(4,1)=u(1,4)=24, however,
at u(1,4) when you evaluate f(1-4) that gives you f(-3) which is out of the boundary in the initial condition for x. how do you re-structure another equation so this would work? thanks

 

[rude man]

New territory for me, so what follows may be nonsense, but:

I get u(x,t) = (1/2){(x-t)² + (x+t)² + ∫6s ds} with lower limit x-t and upper limit x+t.

So u(1,4) = (1/2){(1-4)² + (1+4)² + 48} = whatever.

I guess I don't see where x > 0 is violated anywhere. Of course, x - ct can be negative & is in this instance (c = 1).

Ref: http://www-solar.mcs.st-and.ac.uk/~alan/MT2003/PDE/node12.html