Solving a Word Problem: Preparing Special Eye Drops

  • Thread starter Thread starter Zed
  • Start date Start date
  • Tags Tags
    Eye Word problem
AI Thread Summary
To solve the problem of preparing 16 milliliters of eye drops with a 5% active ingredient using 10% and 1% solutions, two equations are established. The first equation represents the total active ingredient: 0.1x + 0.01y = 0.8, where x is the volume of the 10% solution and y is the volume of the 1% solution. The second equation accounts for the total volume: x + y = 16. By solving these equations simultaneously, the pharmacist can determine the required amounts of each solution. This method ensures the correct formulation of the eye drops for the patient.
Zed
Messages
6
Reaction score
0
Word problem !

Hi ,

This is a Hw question i have am stuck on i don't know how to solve it ...

A pharmacist is to prepare 16 milliliters of special eye drops for a glaucoma patient. The eye-drop solution must have a 5% active ingredient, but the pharmacist only has 10% solution and 1% solution in stock.


How much of 10% solution should be used to fill the prescription?

How much of 1% solution should be used to fill the prescription?


please help

thx
 
Physics news on Phys.org
convert to formulas:
The amount of active solution in each ingredient should sum to the total active solution:
x*.1 + y*.01 = 16*.05
The amount of each ingredition should sum to the total amount:
x + y = 16

Then solve.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top