Solving Collision Between 120kg Tackler and 75kg Halfback

  • Thread starter Thread starter rueberry
  • Start date Start date
  • Tags Tags
    Collision
AI Thread Summary
To solve the collision problem involving a 120 kg tackler and a 75 kg halfback, the conservation of momentum formula is applied. The initial momentum is calculated using the masses and velocities of both players before the collision. After setting up the equation, the common speed after the collision can be determined by solving for V1 and V2, which are equal. The correct application of the formula will yield the common speed immediately after the collision. This approach ensures accurate results in analyzing the dynamics of the collision.
rueberry
Messages
5
Reaction score
0
I have been working on this for some time, maybe I'm just using the wrong formula.

A 120 kg tackler traveling 3 m/sec tackles a 75 kg halfback running 6m/sec in the opposite direction. What is their common speed immediately after the collison?

Thank you.
 
Physics news on Phys.org
Use the formula

(M1 x U1) + (M2 + U2) = (M1 x V1) + (M2 x V2), Conservation of momentum forumla.

where M1 = Tackler Mass
M2 = Halfback Mass
U1 = Tackler Speed
U2 = Halfback speed
V1 = V2 (since the speed after colision is common) = Speed of both of them after the collision.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Inelastic Football Collision Problem
Replies
6
Views
3K
What is the Solution to a Perfectly Inelastic Collision Problem?
Replies
2
Views
4K
The term mutual velocity, can be described as?
Replies
4
Views
4K
How to Calculate Speed of Head of Driver After Collision?
Replies
10
Views
2K
Momentum and Degrees: Calculation and Direction
Replies
2
Views
12K
Ambiguous question on momentum and how it works...
Replies
13
Views
1K
Elastic Collision and Momentum of Ice Skaters
Replies
16
Views
3K
Help Needed: Calculating Mutual Speed After Tackling Collision
Replies
2
Views
2K
What Forces Result from a Football Tackle Involving Inelastic Collision?
Replies
1
Views
9K
Solving Impulse Homework: A, B, C
Replies
11
Views
12K

Hot Threads

Recent Insights

Back
Top