Solving D'Alambert Problem - Integrating g(x)

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SUMMARY

The discussion focuses on solving the D'Alambert problem by integrating the function g(x), defined as g(x) = 1 for -1 < x < 1 and g(x) = 0 otherwise. The user seeks clarification on deriving the system of equations from this integration. The correct solution involves applying the D'Alambert formula to obtain the piecewise function u(x,t) for specified intervals. The derived function is u(x,t) = (x+at+1)/2a for -1-at < x < -1+at, u(x,t) = t for -1+at < x < 1-at, and u(x,t) = (1-x+at)/2a for 1-at < x < 1+at.

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Homework Statement



Untitled.jpg


please see the attachement

Homework Equations



Could somebody explain how to get the the system of equations at the bottom of the page from integrating g(x)?

The Attempt at a Solution




I attempted to integrate, but couldn't get the right answer, do I need to subtract the previous integration from the current one?
 
Last edited:
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Just so you know, we can't download your attachment until a mentor approves it.
 
g(x) = 1 when -1 < x < 1, and g(x) = 0 otherwise

how do I get

u(x,t) = (x+at+1)/2a for -1-at < x < -1+at
= t for -1+at < x < 1-at
= (1-x+at)/2a for 1-at< x<1+at

Thanks
 

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