Solving Definite Integral Problem with Density Function f(x) = 2e^(-0.25x)

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Homework Help Overview

The discussion revolves around a probability density function given as f(x) = 2e^(-0.25x) and the task of finding the probability Pr(X ≤ 3). Participants are exploring the implications of the density function and the correct interpretation of the integral involved.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the necessity of a multiplier k in the context of the density function and whether it should be set to ensure the total integral equals 1. There is confusion about the limits of integration and the definition of the probability function.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem statement and the role of the density function. Some have provided insights into the integral setup, while others express uncertainty about the correct interpretation of the problem.

Contextual Notes

There is ambiguity regarding the range over which the probability density function is defined and whether the original poster has accurately conveyed the problem statement. Participants are attempting to clarify these points to move forward.

maxpayne_lhp
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Hello,

Okay so I was given a density function:

[tex]f(x) = 2e^(-0.25x)[/tex]

The problem asks for the value of Pr(X < or = 3)

I first figured out the probability density function first by let

[tex]\int (3,0) k.25e^(-.25x) = 1[/tex]

And figured out that k = .45

and continue solving my problem until i get the final answer is -.212

So, is my solution correct? Did I misunderstand something about k?

Thanks much!

NN
 
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Sorry, my LaTeX code looks bad.
 
Click this picture to see where your typing went wrong

[tex]k\int_{0}^{\infty} e^{-0.25 x}{}dx =1[/tex]

I don't know about the value of k, whether it's correct or not, guess not...

Daniel.
 
What do you mean, you were "given a density function:
[itex]f(x)= 2e^{-.25x}[/itex]"? You seem to think that you need to find a multiplier k so that the "total integral" (is that supposed to be an integral from 0 to 3?) is 1. If that were the case then you wouldn't be asked for the probability that x is between 0 and 3: it would be 1!

Dextercioby, on the other hand, seems to think that you need to find k such that the integral from 0 to infinity is 1.

I see that we are already told that the function is [itex]2e^{-.25x}[/itex]. That is, that the "k" is 2, but that we are not given an interval over which this is to be the probability density.
 
Daniel, yeah thanks for the code... i meant

[tex]k\int_{0}^{3} e^{-0.25 x}{}dx =1[/tex]

HallsofIvy, Uh... Thats the same word from the problem in the book... and yes, thats the integral from 0 to 3... I am not sure I know about the total integral...

Sorry about the confusion.
 
Then please state the problem exactly, word for word. So far you have told us that the density function is [tex]f(x) = 2e^{-0.25x}[/tex]
that [tex]k\int_{0}^{3} e^{-0.25 x}{}dx =1[/tex]
and that the problem asks for the probability that x is less than or equal to 3. I'm afraid none of that makes much sense to me. What exacly is the probability function and over what range is it defined?
 

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