thundercleese
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I get close to the answer but just not seeing where the integers in the answers are coming from, perhaps forgetting a constant? This is a EE circuit analysis class.
Given y(t) = dx(t)/dt
a. Find x(t) if y(t)=
Part a
y(t)=[itex]\frac{dx(t)}{dt}[/itex]
when y(t) = 0:
∫0 = ∫[itex]\frac{dx(t)}{dt}[/itex]
0 = x(t) (this part agrees with given answer)
when y(t) = e[itex]^{-t}[/itex]:
∫ e[itex]^{-t}[/itex]=∫[itex]\frac{dx(t)}{dt}[/itex]
-e[itex]^{-t}[/itex]=x(t)
part b, y(t)=t[itex]^{2}[/itex]:
∫t[itex]^{2}[/itex] = ∫[itex]\frac{dx(t)}{dt}[/itex]
[itex]\frac{1}{3}[/itex]t[itex]^{3}[/itex] = x(t)
Given answers:
part a: 0, t[itex]\leq[/itex]0; (1-e[itex]^{-t}[/itex]), t[itex]\geq[/itex]0
part b: [itex]\frac{1}{3}[/itex](2+t[itex]^{3}[/itex]), t [itex]\geq[/itex]1
Homework Statement
Given y(t) = dx(t)/dt
a. Find x(t) if y(t)=
0 : t<0;
e[itex]^{-t}[/itex] : t>0
b. Find x(t) for t=1 if x(1)=1 and y(t)=t[itex]^{2}[/itex] for t[itex]\geq[/itex]1The Attempt at a Solution
Part a
y(t)=[itex]\frac{dx(t)}{dt}[/itex]
when y(t) = 0:
∫0 = ∫[itex]\frac{dx(t)}{dt}[/itex]
0 = x(t) (this part agrees with given answer)
when y(t) = e[itex]^{-t}[/itex]:
∫ e[itex]^{-t}[/itex]=∫[itex]\frac{dx(t)}{dt}[/itex]
-e[itex]^{-t}[/itex]=x(t)
part b, y(t)=t[itex]^{2}[/itex]:
∫t[itex]^{2}[/itex] = ∫[itex]\frac{dx(t)}{dt}[/itex]
[itex]\frac{1}{3}[/itex]t[itex]^{3}[/itex] = x(t)
Given answers:
part a: 0, t[itex]\leq[/itex]0; (1-e[itex]^{-t}[/itex]), t[itex]\geq[/itex]0
part b: [itex]\frac{1}{3}[/itex](2+t[itex]^{3}[/itex]), t [itex]\geq[/itex]1