Solving Diode Resistor Circuit Homework

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SUMMARY

The discussion focuses on solving a diode resistor circuit homework problem involving the calculation of voltage and current across each diode in a series circuit. The key equations used include the diode equation, V = 0.04654 * ln(I/(0.62E-19)) + I*6.97, and the wire resistance formula, R = pl/A = 0.02 ohms. The final results indicate a diode voltage of 2V and a current of 20mA. Participants confirm that diode currents and voltages increase as one approaches the power source, affirming the correctness of the approach taken.

PREREQUISITES
  • Understanding of diode equations and characteristics
  • Knowledge of Ohm's Law (V = IR)
  • Familiarity with wire resistance calculations (R = pl/A)
  • Basic circuit analysis skills
NEXT STEPS
  • Study the diode equation in detail to understand its implications on circuit behavior
  • Learn about series and parallel circuit configurations
  • Explore advanced circuit simulation tools like LTspice for practical applications
  • Investigate the effects of temperature on diode performance
USEFUL FOR

Electrical engineering students, hobbyists working on circuit design, and anyone involved in electronics troubleshooting or diode application analysis.

yoyo13
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Homework Statement



Find Voltage/Current across each diode:

----R---
|...|
V...D
|... |
----R---

Repeat 50x until:

----R----
...|
...D
...|
----R----

V = power source
D = diode
R = wire resistance
. = empty space

Homework Equations



for diode:
V = 0.04654 * ln(I/(0.62E-19)) + I*6.97

for wire:
R = pl/A = 0.02 ohms

Final diode voltage = 2V
Final diode current = 20mA

The Attempt at a Solution


Attempted to use v = ir with wire resistance to find voltage over last-1 diode, but did not work out as current got higher as worked back to source.
 
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Welcome to PF :smile:

It took me a while to figure out how the circuit looks from your description.

It sounds like you are on track to solving this. The diode currents (and voltages) should get higher as you get closer to the source.
 

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