Solving Elastic Collision Homework: Player 2's Final Velocity

AI Thread Summary
In the discussion about an elastic collision between two football players, the calculations for Player 2's final velocity were performed using the provided formula. Player 1, with a mass of 75 kg and an initial velocity of 6 m/s, and Player 2, with a mass of 150 kg and an initial velocity of -3 m/s, were analyzed. The calculated final velocity for Player 2 was found to be 3 m/s, while an online solution suggested it should be -3 m/s. This discrepancy raised questions about potential errors in sign or misunderstanding of momentum principles. The conclusion highlights confusion regarding the implications of the online solution, which suggests Player 2's velocity remains unchanged post-collision.
LSarah6
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Homework Statement


A collision occurs between two football players. Player 1 has mass of 75 kg and a velocity of 6 m/s. Player 2 has mass of 150 kg and a velocity of -3 m/s. Assuming an ELASTIC collision, what is the final velocity of player 2?


Homework Equations


They gave us this equation in class to calculate the final velocity:
m = mass
Vi = initial velocity
Vf = final velocity
a = player 1
b = player 2

Vfb = [(2*ma)/(ma+mb)]*Via + [(mb-ma)/(ma+mb)]*Vib


The Attempt at a Solution


Using the equation above and plugging in the numbers:

Vfb =
[(2*75kg)/(75kg + 150kg)]*(6 m/s)
+
[(150kg - 75kg)/(75kg + 150kg)]*(-3 m/s)

which gives me:

Vfb = 4 m/s + -1 m/s = 3 m/s


The "online" homework solution says it is -3 m/s. Am I incorrect? Did I miss a negative sign somewhere, or is there a principle of momentum that I am not getting?
 
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LSarah6 said:
The "online" homework solution says it is -3 m/s.
That answer implies that the velocity of the 2nd player is unchanged by the collision--which makes no sense.
 
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