Solving Energy Work Problem: Joe's Car, 300N, 10000N, 200m, 3min

AI Thread Summary
Joe exerts a force of 300 Newtons to move his car 200 meters, leading to a calculation of work done using the formula W=FΔXcosθ. The weight of the car, 10,000 Newtons, does not affect the work calculation since the angle is zero, making cos(0) equal to one. The time taken, 3 minutes, is irrelevant for the work calculation in this context. The resulting work done is 60,000 Joules. This straightforward approach clarifies the solution without overcomplicating the factors involved.
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Homework Statement



Joe exerts a force of 300 Newtons to move his car, which has run out of gas. How much work has he done if he moves the car 200 meters in 3.0 minutes?
Note that the car weighs 10000 Newtons.


Homework Equations



W=F\DeltaXcos\theta

W=work
F=force
\DeltaX=change in location
cos \theta= cos of angle

The Attempt at a Solution



I have solved similar problems by plugging in the force given but I do not know how the weight of the car plays into solving the problem. I know that there is no angle so you just do the cos of zero which is one and delta x would be 200m.
So what my main question is, as I stated before, is how the weight of the car comes into solving the problem and also the 3 minutes?
 
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cheerspens said:

Homework Statement



Joe exerts a force of 300 Newtons to move his car, which has run out of gas. How much work has he done if he moves the car 200 meters in 3.0 minutes?
Note that the car weighs 10000 Newtons.


Homework Equations



W=F\DeltaXcos\theta

W=work
F=force
\DeltaX=change in location
cos \theta= cos of angle

The Attempt at a Solution



I have solved similar problems by plugging in the force given but I do not know how the weight of the car plays into solving the problem. I know that there is no angle so you just do the cos of zero which is one and delta x would be 200m.
So what my main question is, as I stated before, is how the weight of the car comes into solving the problem and also the 3 minutes?
Using your correct definition of work, maybe they don't?
 
Well in that case you get an answer of 60000 Joules?
 
cheerspens said:
Well in that case you get an answer of 60000 Joules?

Yes!
 
Much simpler than I made it out to be. Thank you!
 
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