MHB How Do You Solve These Simultaneous Equations?

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This discussion focuses on solving simultaneous equations involving complex numbers. The equations derived from the original expression (3 + 2i)x - (1 - 2i)y = 1 + 6i are 3x - y = 1 and 2x + 2y = 6. The solution process involves equating the real and imaginary components, leading to a system of linear equations. Participants confirm the method and provide clarity on the separation of real and imaginary parts.

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Yordana
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Determine the real numbers x and y from the equations:
1658397240563.png
I would appreciate it if someone could show me the solution to the first sub point.. 😢
 
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Yordana said:
Determine the real numbers x and y from the equations: View attachment 11876 I would appreciate it if someone could show me the solution to the first sub point.. 😢
The idea is that the real and imaginary components are the same on both sides of the equations. So for the first part:
(3 + 2i)x - (1 - 2i)y = 1 + 6i

(3x - y) + (2x + 2y)i = 1 + 6i

So now you have the simultaneous equations
3x - y = 1
2x + 2y = 6

-Dan
 
topsquark said:
The idea is that the real and imaginary components are the same on both sides of the equations. So for the first part:
(3 + 2i)x - (1 - 2i)y = 1 + 6i

(3x - y) + (2x + 2y)i = 1 + 6i

So now you have the simultaneous equations
3x - y = 1
2x + 2y = 6

-Dan
Thank you!
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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