Solving Esther's Morning Commute Problem

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Esther's morning commute problem involves calculating the distance she drove to work based on her average speeds of 40 mph in the morning and 30 mph in the evening, with a total commuting time of one hour. The equations derived from her speeds and times lead to the relationship 40(p) = 30(q), where p is the morning time and q is the evening time. After solving the equations, it is determined that q equals approximately 34.29 minutes and p equals about 25.71 minutes. The final calculation reveals that Esther drove approximately 23.80 miles to work in the morning. The discussion highlights the importance of careful arithmetic and algebraic manipulation in solving the problem accurately.
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Homework Statement


Esther drove to work in the morning at an average speed of 40 miles per hour. She returned home in the evening along the same route and averaged 30 miles per hour. If Esther spent a total of one hour commuting to and from work how many miles did Esther drive to work in the morning?



Homework Equations





The Attempt at a Solution


40(time she took in the morning, or p) = x
30(time she took in the evening, or q) = x

Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-9q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, p (the time she took in the morning) must equal 25.714285.
Then (25.714285/60) x 40 = 23.80 miles I think

Am I correct?
 
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maria vega said:
Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

It's not worth the fraction of a second it takes to divide by 2 and get 4p = 3q?
maria vega said:
Therefore 8(60-q) = 6q or 480-9q = 6q.

Where did the 9 come from?

EDIT: Just realized you canceled out that mistake with another one by saying that the sum of the q terms was 14q (the correct answer) even though what you wrote would have yielded 15q as a result.

EDIT 2: Although your numerical answers for p and q seem correct, your final answer for the distance is not correct.
 
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ok Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-8q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, 30 x (34.825/60) = 17.1425 is this it? the distance of his house to the office
 
maria vega said:
ok Therefore 40(p) = 30(q), or divide both sides by 5 and get 8(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.

LOL. This doesn't make any more sense than it did the first time you wrote it. They're both even numbers. It takes almost no time for the extra step of dividing them by 2.

maria vega said:
Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.

Therefore 8(60-q) = 6q or 480-8q = 6q. So 480 = 14q, which makes q = 34.2857 If q = 34.2857, then by (p+q)=60, 30 x (34.825/60) = 17.1425 is this it? the distance of his house to the office

Yeah, that answer seems about right.
 
thank youuu!
 
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