Solving for a variable integral

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SUMMARY

The discussion revolves around finding the exact positive value of c such that the area between the function f(x) = x² - c² and the x-axis equals 36. The initial approach involved calculating the antiderivative incorrectly as F(x) = x³/3. The correct antiderivative should be F(x) = (1/3)x³ - c²x, leading to the area calculation of 2(c³/3 - c²c) over the interval [-c, c]. The correct value of c, derived from setting the area equal to 36, is approximately 3.78.

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Homework Statement


Find the exact positive value of c if the area between f(x)=x^2-c^2 and the x-axis is equal to 36.



The Attempt at a Solution



My first step is to take the antiderivative of f(x), giving me F(x)=x^3/3 then applying the fundamental theorem on the interval [-c,c] since that's where the function should cross the x axis.

This gives me 2c^3/3. If I set this equal to 36 I should get the value of c. Solving I get 3*(2)^(1/3) = aprox. 3.78. however if take the integral of x^2-(3.78)^2 on [-3.78,3.78] I get -72 So I'm not sure what I'm doing wrong or where to go from here. Thanks from the help
 
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armolinasf said:

Homework Statement


Find the exact positive value of c if the area between f(x)=x^2-c^2 and the x-axis is equal to 36.



The Attempt at a Solution



My first step is to take the antiderivative of f(x), giving me F(x)=x^3/3
Stop here. The function is f(x) = x2 - c2, so its antiderivative is not (1/3)x3.
armolinasf said:
then applying the fundamental theorem on the interval [-c,c] since that's where the function should cross the x axis.

This gives me 2c^3/3. If I set this equal to 36 I should get the value of c. Solving I get 3*(2)^(1/3) = aprox. 3.78. however if take the integral of x^2-(3.78)^2 on [-3.78,3.78] I get -72 So I'm not sure what I'm doing wrong or where to go from here. Thanks from the help
 
Wow, Thanks for pointing that one out...I figured it out
 

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