Solving for d in Bragg's Law | Quick Question

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SUMMARY

This discussion focuses on solving for the interplanar spacing (d) in Bragg's Law, represented by the equation 2d sin(θ) = nλ. The user has calculated the wavelength (λ) and obtained multiple Bragg angles (θ) but is uncertain whether to use the first angle with n=1 or to average the results from all angles (θ1 to θ4) with their corresponding n values (1 to 4). The consensus suggests that using all four data points to establish a linear relationship is optimal, allowing for the calculation of d as the slope of the linear regression of sin(θ) against n.

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Homework Statement


I am inquiring about Braggs Law [tex]2 d\sin\theta = n\lambda[/tex].
The question I'm working on gives me the first four Bragg angles ([tex]\theta[/tex] values) and I have also calculated the wavelength of the light. I want to solve for d but I am unsure what value to use.

Homework Equations


Rearranging for d: [tex]d = \frac{n\lambda}{2\sin\theta}[/tex]

The Attempt at a Solution


I seem to have multiple options. Using the different [tex]\theta[/tex] values with the corresponding n value (n=1,2,3,4) gives a different answer for d each time. I'm not sure whether to use just the first value ([tex]\theta_1[/tex] and n=1) or whether I should sum them all and divide by 4 to get an average? This site http://www.bruker-axs.de/fileadmin/user_upload/xrfintro/sec1_8.html (1/4 of the way down) suggests that each [tex]\theta[/tex] and corresponding n value account for different reflection orders. To me this sounds like the best value would be getting the average but I just want to make sure.

i.e. [tex]d = \frac{1}{4}\left(\frac{\lambda}{2\sin\theta_1}+...+\frac{4\lambda}{2\sin\theta_4}\right)[/tex]

What do you think?
 
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Plot sin(theta) against n. This is a linear equation with a slope of lambda/2d. If you know lambda, you can get d.
 

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