Solving for Domain and Asymptotes in Functions f(x) and g(x)

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The discussion focuses on determining the domain, vertical and horizontal asymptotes, and intercepts for the functions f(x) = -log3(x - 1) + 2 and g(x) = 3 - x + 1 - 9. For f(x), the domain is established by identifying when the logarithm is defined, specifically requiring x to be greater than 1. The participants clarify that the logarithm does not exist for zero or negative values, which is crucial for finding the domain. For g(x), the conversation shifts to finding the horizontal asymptote and intercepts, with similar principles applied. Overall, the thread emphasizes understanding logarithmic functions and their implications for domain and asymptotes.
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Please Help with Domain...

Homework Statement



For f(x) Determine Domain, Vertical Asymptote and x and y intercepts. then State and graph the effect of the modifications and sketch the graph of f(x)
Given f(x) = - log3(x – 1) + 2


For g(x) determine domain, Horizontal asymptote and x and y intercepts. then state and graph the effect of the modifications and sketch the graph of g(x)
Given g(x) = 3 - x + 1 - 9
 
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Lets begin with the first problem. To find the domain, consider when the log of something not exist. Let me know if this is what's confusing you.
 
yes that is a confusing part, I know how to find the Domain, but not when involving log
 
Ok, so let's say I have y = log( 2 - x) - 1, and I want to find the domain of the function. You should know that the log of zero, or any negative quantity does not exist. So I would set the function inside of the log equal to zero:

2 - x = 0 ---> x = 2.

Now I know that the function exists as long as x is greater than 2. It does not exist when x is two or less. This is our domain. Does that make sense?
 
yes thank you.
 
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