Solving for Isomorphic Subgroups: F/K and the Additive Group of Functions

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The discussion focuses on finding a subgroup of the additive group of functions F that is isomorphic to the quotient group F/K, where K consists of constant functions. Participants explore the use of the Fundamental Homomorphism Theorem to define a homomorphism phi from F to itself, specifically phi(f(x)) = f(x) - f(0). It is established that the kernel of this function includes all constant functions, and the image consists of functions that equal zero at the origin. The conclusion drawn is that F/ker(phi) is isomorphic to phi(F), effectively solving the problem. The conversation emphasizes understanding the problem rather than relying solely on complex theorems.
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[SOLVED] group of functions

Homework Statement


Let F be the additive group of all functions mapping R into R. Let K be the subgroup of F consisting of the constant functions. Find a subgroup of F to which F/K is isomorphic.

Homework Equations


The Attempt at a Solution


I have absolutely no idea how to do this. Am I supposed to use the fundamental homomorphism theorem? Is it the set of all functions such that f(0)=0? How in the world would you prove that?
 
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The cosets of the quotient group are {f(x)+C} where C varies over the elements of K (konstants) for a given f(x). Pick a representative of each coset in such a way as to form a group. Picking an f(x) such that f(0)=0 works great. So does picking an f(x) such that f(2)=0. You don't need any big theorems. You just need to understand the problem.
 
Here is how you would use the Fundamental Homomorphism Theorem:

Define phi from F to F by phi(f(x)) = f(x)-f(0). It is clear that the kernel of this function is going to be all of the constant functions. It is also clear that the image of this function will hit all the members of F that are 0 at 0. Then the FHT tells us that F/ker(phi) is isomorphic to phi(F) and we are done.
 
For somebody that had "absolutely no idea how to do this", that's really well done. Keep it up! Note f(x)-f(2) for works for phi as well. I kinda like 2.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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