Solving for Planet Islander's Radius from a Projectile Launch

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A projectile is launched vertically from Planet Islander at one-third the escape speed, reaching a maximum height above the surface. The escape speed formula is given as the square root of G multiplied by mass divided by radius squared. To find the radius, the conservation of mechanical energy must be considered, equating the kinetic energy at launch with the potential energy at maximum height. The discussion highlights confusion regarding the correct equations to use and the relationship between height and radius. Ultimately, mechanical energy conservation is confirmed as applicable in this scenario, assuming no atmospheric interference.
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Homework Statement


a projectile of mass m is launched vertically from the surface of Planet Islander at a speed that is one-third the escape speed from the surface. If the projectile reaches a maximum height that is a distance h from the surface of the planet, what is the radius of planet islander?


Homework Equations



Escape Speed = square root of G*mass/radius^2


The Attempt at a Solution



Is this the correct equation:

1/3 (G*mass/r + h) = G*mass/r

so the radius is equal to 9h? or is it 3h? or h/9?

I am confused as what to what equations to equate? and where the height comes in?

Please help!
 
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Your formula for the escape speed and none of the solutions you suggest are correct. You need that, and a consideration of the potential and kinetic energies involved at two interesting points of the projectiles flight in order to solve this problem.
 
is energy conserved in this problem? so we can equate energy at the peak and energy just before it is launched?
 
Yes, mechanical energy is conserved if you make the assumption that there are no atmosphere.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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