Solving for Side Length of Right Pyramid with Height/Volume

AI Thread Summary
To find the side length of a right pyramid with a known volume of 554.9 and height of 15.1, the formula for volume, V = (1/3)lwh, can be rearranged. The base area can be calculated as lw = 3V/h, but l and w cannot be determined separately without additional information. If the base is square, the side length can be found using the formula s = √(3V/h). Substituting the values gives s = √(3 * 554.9 / 15.1). This approach provides a clear method to solve for the side length of the pyramid.
Shannog
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Homework Statement



Basically the volume of the pyramid is 554.9 and its height is 15.1. I know that the forumla to find the volume of a pyramid is V=1/3lwh but I'm too dumb to figure out how to switch it around to make it work.

The Attempt at a Solution



I don't even know where to start!
 
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V= (1/3)lwh is the volume of a pyramid with rectangular base with side lengths l and w and height h. If you know the volume of the pyramid, V, and height l, then you can solve for the base area as lw= 3V/h. You cannot solve for l and w separately- they can be any numbers that multiply to give 3V/h. If you know the base is square, with side lengths l= w= s, you have s^2= 3V/h then s= \sqrt{3V/h}.
 
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