Solving For t in A Sin(Bt) - Ct + D = 0

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To solve the equation A sin(Bt) - Ct + D = 0 for t, it is necessary to recognize it as a transcendental equation, which typically requires numerical or graphical methods. The equation can be rearranged to A sin(Bt) = Ct - D, allowing for easier analysis. By plotting both sides of the equation on a graph, the intersection points will indicate the values of t that satisfy the equation. This method effectively visualizes the solutions, as the left side represents a sinusoidal function while the right side is linear. Utilizing graphical solutions is essential for finding t in this context.
KLoux
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Hello,

I have an equation which I am trying to solve for t. Of course the problem I'm having is due to the combination of ts within the argument of the sin term and also outside of it. I think I could also manage without the constant D (using sin(x)/x=sinc(x)), but that's no help here (as far as I can tell). Any advice is appreciated! Here's the equation:

<br /> A \sin \left( B t \right) - C t + D = 0<br />

Thanks,

Kerry
 
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This is a transcendental equation which has to be solved numerically or graphically. First rewrite the equation with the sin term on the left and the linear term on the right:

A sin(Bt) = Ct - D

Now plot on the same graph, the function on the left and the function on the right. Their intersection gives the value of t which solves your original equation
 
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