Solving for the Length of a Cubical Tank using Related Rates

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Homework Help Overview

The discussion revolves around a problem involving a cubical tank where water is flowing in at a specified rate, and the height of the water is increasing at a certain rate. The goal is to determine the length of each side of the tank using related rates.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply related rates by differentiating the volume equation of the cube and substituting values for the flow rate and the rate of height increase. Some participants question the use of units in the equations and suggest a dimensionless approach. Others seek clarification on the reasoning behind specific expressions used in the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions made in the calculations. Some guidance has been offered regarding the treatment of units, but there is no explicit consensus on the correct approach or final equation.

Contextual Notes

There is a noted confusion regarding the conversion of units and the implications of using dimensional analysis in the problem. The original poster expresses uncertainty about the correctness of their solution and is seeking further clarification.

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Homework Statement


Water flows into a cubical tank at a rate of 19 L/s. If the top surface of the water in the tank is rising by 3.7 cm every second, what is the length of each side of the tank?


Homework Equations


v=L^3


The Attempt at a Solution


so what I started doing was

dV/ds = 3l^2 dl/ds
changed 19 L/sec into cm^3 which is 19000
19000 = 3l^2(3.7)
19000 = 11.1l^2
divided both sides by 11.1
1711.71 = l^2
then took the square root of both sides to get
41.37 cm
however when i put in the answer for my homework, it says the answer is wrong, i have 10 tries, so i was wondering what am i doing wrong or what is the right way to do this problem
 
Physics news on Phys.org
1 Liter is a cubic decimeter
 
1 liter is also 1000 centimeters^3
 
shortman12012 said:

Homework Statement


Water flows into a cubical tank at a rate of 19 L/s. If the top surface of the water in the tank is rising by 3.7 cm every second, what is the length of each side of the tank?


Homework Equations


v=L^3


The Attempt at a Solution


so what I started doing was

dV/ds = 3l^2 dl/ds
changed 19 L/sec into cm^3 which is 19000
19000 = 3l^2(3.7)
19000 = 11.1l^2
divided both sides by 11.1
1711.71 = l^2
then took the square root of both sides to get
41.37 cm
however when i put in the answer for my homework, it says the answer is wrong, i have 10 tries, so i was wondering what am i doing wrong or what is the right way to do this problem

Sometimes, in problems like this one, you get nothing but trouble if you use units within your equations. It is better to express things like this: the inflow rate is V liter/sec, where V = 19. (Here, V is dimensionless.) If the sides of the tank have length x cm, the flow rate in cm^3 per sec is 3.7*x^2. (Note: here, x is dimensionless, as is the 3.7, because I said the width was x cm and 3.7 is the number of cm per second.) Now just clear up liters vs cm^3 and you are done.

RGV
 
sorry but I'm not following you on your explanation. I understand about taking out all the units, but then where did you get 3.7*x^2 from and what is the final equation you are using?
 

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