Solving for Theta: A Physics-Math Dilemma

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Homework Help Overview

The discussion revolves around solving for the angle theta in a physics-related problem that has been framed as a mathematical question. The original poster presents two equations involving tension (T) and trigonometric functions of theta, seeking assistance in determining the value of theta.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore various methods to manipulate the given equations, including simplification and substitution. Some suggest dividing the equations to express tan(theta) in terms of known constants. Others question the legality of these manipulations and the validity of the steps taken.

Discussion Status

The discussion is active, with participants providing guidance on potential approaches to solving the equations. There is a focus on validating the steps taken and exploring different methods without reaching a consensus on a final solution.

Contextual Notes

Participants note the importance of ensuring that T is not equal to zero in their manipulations. The original equations and their transformations are under scrutiny, with some questioning the assumptions made during the problem-solving process.

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Homework Statement



This is originally from a physics problem but it's more of a math question. How do I solve for theta?

Homework Equations



400 - Tcos(theta) = 0

-200 + Tsin(theta) = 0

Using those equations, I need to solve for theta. Also, knowing that tan(theta) = sin(theta)/cos(theta) is supposed to be relevant to this.

The Attempt at a Solution



All I did was simplify the equations to 200 - Tcos(theta) + Tsin(theta) = 0

Not sure if that was a good idea or not but I'm suck.
 
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Ryuk1990 said:

Homework Statement



This is originally from a physics problem but it's more of a math question. How do I solve for theta?

Homework Equations



400 - Tcos(theta) = 0

-200 + Tsin(theta) = 0

Using those equations, I need to solve for theta. Also, knowing that tan(theta) = sin(theta)/cos(theta) is supposed to be relevant to this.

The Attempt at a Solution



All I did was simplify the equations to 200 - Tcos(theta) + Tsin(theta) = 0

Not sure if that was a good idea or not but I'm suck.
Your equations can be rewritten as
Tsin(theta) = 200
Tcos(theta) = 400

Instead of adding equations to each other, what about dividing each side of one equation by the corresponding side of the other?
 
Place all the constants on one side of the equality for each of the equations.

Then remember that sin2θ+cosθ=1.

so something like R2sin2θ+R2cos2θ=1
 
Mark44 said:
Your equations can be rewritten as
Tsin(theta) = 200
Tcos(theta) = 400

Instead of adding equations to each other, what about dividing each side of one equation by the corresponding side of the other?

Do you mean as in like this?

tan(theta) = 200/400

Is this legal?
 
Yes :smile:

You can even take a slower approach to solve the two simultaneous equations:

[tex]Tsin\theta=200[/tex] (1)

[tex]Tcos\theta=400[/tex] (2)

Re-arrange (1) : [tex]T=200csc\theta[/tex] (3)

Substitute (3) into (2) : [tex]200csc\theta cos\theta=400[/tex]

Simplify : [tex]tan\theta=1/2[/tex]

So yes, if you are convinced that substitution is a valid step in solving simultaneously, then the process of dividing both equations together is also.
 
Ryuk1990 said:
Do you mean as in like this?

tan(theta) = 200/400

Is this legal?
Sure, it's legal, as long as T isn't 0, and I'm reasonably sure in this problem it isn't. Once you get a value for theta, then substitute into either of the original equations to find T.
 

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