Solving for Time in Scalar Product Equation

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The discussion revolves around solving the equation d = !(v + 0)t for time (t), with given values of d = 0.984 and v = 1.9. The user is confused about the "!" symbol in the equation, which is not standard in this context. Another participant suggests that it might be a notation error and proposes that the equation could be d = |(v + 0)t|, indicating a scalar product of velocity and time. The user attempts to solve for t by ignoring the "!" but finds that their calculated value does not yield the correct result. Clarification on the equation's notation is essential for accurate problem-solving.
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Homework Statement


I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"



Homework Equations


d = !(v + 0)t;



The Attempt at a Solution


In a problem with different numbers I was able to solve for t by dividing and ignoring the "!", then multiply by 2 for the answer.
.984/1.9= .518
.518 * 2 = 1.036 but this does not work.
 
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hi kkershaw

not too sure what you're trying to do - can you explain the whole problem...?
 
kkershaw said:

Homework Statement


I am solving for t using this equation: d = !(v + 0)t;
My d=.984 and v=1.9
I don't know what to do with the "!"

Are you sure it's not

d = |(v + 0)t| ?

expressing d as a scalar product of velocity (speed) and time?
 

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