Solving for Vo in terms of Vs/Vx

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Discussion Overview

The discussion revolves around solving for the output voltage (Vo) in terms of the source voltage (Vs) and the voltage across a certain point (Vx) in a circuit involving resistors. Participants explore various methods including voltage division and Ohm's law, while addressing potential errors in calculations and unit conversions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants propose using voltage division to find Vx, with initial calculations suggesting Vx = Vs(R1/(R1+R2)).
  • One participant claims to have found Vo as (5/18)Vx, but another questions the validity of this expression.
  • A later reply suggests Vx = (2/5)Vs and calculates Vo as (5/6)(1/0.3)Vx, but acknowledges a mistake in the calculation.
  • Participants discuss the implications of using a controlled current source, with one asserting that Volts x Siemens = Current.
  • There is a clarification regarding the units of the resistors, with a participant confirming their values in kiloohms and calculating their parallel combination.
  • Another participant arrives at Vo = 250Ω*Vx and expresses uncertainty about substituting Vx into Vo without a value for Vs.
  • One participant suggests that a symbolic solution is acceptable, emphasizing that the goal is to express Vo in terms of Vs.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of calculations and the interpretation of units, indicating that multiple competing views remain without a consensus on the final expressions for Vo and Vx.

Contextual Notes

Participants note potential errors in resistor combinations and current expressions, highlighting the importance of unit consistency and the need for careful calculations. Some assumptions about the circuit configuration may also be implicit.

eatsleep
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http://imgur.com/xe52P30
2. Vx= Vs(R1/R1+R2), V=IR
3. I combined the 1k Ω and 5k Ω resistors then used voltage division to find Vx. I used Vx to find Vo which I found to be (5/18)Vx. I don't know where I can do KCL or KVL to solve for Vx.
 
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eatsleep said:
attachment.php?attachmentid=58937&stc=1&d=1369225726.gif



2. Vx= Vs(R1/R1+R2), V=IR



3. I combined the 1k Ω and 5k Ω resistors then used voltage division to find Vx. I used Vx to find Vo which I found to be (5/18)Vx. I don't know where I can do KCL or KVL to solve for Vx.

You used voltage division to find Vx. What did you get?

Can you show your work for finding Vo in terms of Vx? The expression you gave doesn't look right to me.
 

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Doing voltage division I found Vx = (2/5)Vs. After combining the two resistors on the right side and doing ohm's law I found that Vo = (5/6)(1/.3)Vx = (mistake) is 5/1.8=2.8Vx.
 
Check your value for the combined resistors. Pay attention to the units used. Also take a look at your current expression; why do you divide by 0.3S? The current is specified to be 0.3S*Vx.
 
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gneill said:
Check your value for the combined resistors. Pay attention to the units used. Also take a look at your current expression; why do you divide by 0.3S? The current is specified to be 0.3S*Vx.

Does .3S not mean .3 Siemens = 1/Resistance ?
 
eatsleep said:
Does .3S not mean .3 Siemens = 1/Resistance ?

Yes. And Volts x Siemens = Current. That's a controlled current source.
 
gneill said:
Yes. And Volts x Siemens = Current. That's a controlled current source.

Ok, so then Vo=.25Vx?, I also have Vx=.4Vs
 
eatsleep said:
Ok, so then Vo=.25Vx?, I also have Vx=.4Vs

Again, what are the units for the two resistors in parallel? How many ohms does their parallel combination make? Your expression for Vx looks okay.
 
gneill said:
Again, what are the units for the two resistors in parallel? How many ohms does their parallel combination make? Your expression for Vx looks okay.

They are in kiloohms, their parallel combination makes (5*1)/(5+1) = 5/6 kΩ, 833Ω
 
  • #10
eatsleep said:
They are in kiloohms, their parallel combination makes (5*1)/(5+1) = 5/6 kΩ, 833Ω

Right. Or, if you want to retain accuracy, call it 5000/6 = 2500/3 Ohms. So multiplying your 0.3Vx by 2500/3 gives...
 
  • #11
Vo=250Ω*Vx, so now I have Vx = .4Vs and Vo = 250Vx. I could substituite Vx into Vo, but I do not have a value for Vs.
 
  • #12
eatsleep said:
Vo=250Ω*Vx, so now I have Vx = .4Vs and Vo = 250Vx. I could substituite Vx into Vo, but I do not have a value for Vs.

Nor do you need one... you are looking for Vo in terms of Vs, so a symbolic solution is fine.
 
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  • #13
gneill said:
Nor do you need one... you are looking for Vo in terms of Vs, so a symbolic solution is fine.

Oh well then, thanks for the help.
 

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