Solving for work Power equations

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Bicyclists in the Tour de France exert significant power, with Lance Armstrong generating an average of 6.50 W/kg during a race. For a 155-km race at an average speed of 12.3 m/s, he performs approximately 6,143,293 joules of work. When converted to nutritional Calories, this equates to about 1,466.846 Calories. There is a slight discrepancy in calorie calculations, with one participant noting a result of 1,467.6 Calories. Accurate rounding and unit conversions are essential for precise results.
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Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generated by Lance Armstrong (m = 75.0 kg) is 6.50 W per kilogram of his body mass. (a) How much work does he do during a 155-km race in which his average speed is 12.3 m/s? (b) Often, the work done is expressed in nutritional Calories rather than in joules. Express the work done in part (a) in terms of nutritional Calories, noting that 1 joule = 2.389 x 10-4 nutritional Calories.

(avg)P=w/t

ke=1/2mv^2

w=KEf - KEi

(avg)P= F * S(avg)
 
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the answer for those numbers is:

A: 6143292.682926829 J
B: 1466.846 Calories
 
eanderson said:
the answer for those numbers is:

A: 6143292.682926829 J
B: 1466.846 Calories

Looks good. watch the rounding though... I'm getting 1467.6 calories...
 
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