Solving Frictional Force: Find Ff & Kinetic Friction Coefficient

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A force of 1.6N is applied to a 1.8Kg box, resulting in an acceleration of 0.6m/s². To find the frictional force (Ff) and the coefficient of kinetic friction (mk), the net force is calculated using F=ma, leading to Ff being derived from the difference between the applied force and the net force. The textbook approach suggests using Ff=ma directly, but both methods ultimately yield the same results. The correct understanding involves recognizing that F_net equals the applied force minus the kinetic friction force. This discussion clarifies the relationship between applied force, net force, and friction in solving for kinetic friction.
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[SOLVED] URGENT---Frictional force

A force of 1.6N is applied to a box of mass 1.8Kg. It accelerates 0.6m/s^2. Determine Ff and the coefficient of kientic friction.

K so I knoe how to do this. But in the textbook, it has been done in a different way.

So what I did is Found the net force using F=ma.
Then i subtract from 1.6 and get Ff.
Then use the formula mk= Ff/Fn

In the book they took Ff=ma
Which is the right solution?
 
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Well F_{net}=F_{applied}-F_k where F_k is the force due to kinetic friction. So with a bit of manipulating one can see that the friction force will be the applied force minus the net force which can be worked out from the acceleration of the block.
 
And fnet is MA
 
pinkyjoshi65 said:
And fnet is MA

Yes.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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