MHB Solving how many square inches within a flag

  • Thread starter Thread starter wtam1100
  • Start date Start date
  • Tags Tags
    Square
AI Thread Summary
The discussion focuses on calculating the area of a white stripe on a flag, identified as a parallelogram. To find the area, the formula A = base x height is used, with dimensions of 72 inches for the base and 8.5 inches for the height. Participants confirm that the area calculates to 612 square inches. A diagram is suggested as a helpful tool for understanding the problem. The conversation emphasizes the importance of identifying the correct measurements for accurate area calculation.
wtam1100
Messages
2
Reaction score
0
Hello all. I'm new here. Trying to help my daughter with her homework but I can't solve this problem wondering if there is any out there that is willing to help. Thanks a Head of time.

View attachment 1914
 

Attachments

  • IMG_3969_zpsce16cc03.jpg
    IMG_3969_zpsce16cc03.jpg
    75.3 KB · Views: 103
Mathematics news on Phys.org
Re: Solving how many square inches with in a flag

The white stripe is a parallelogram, whose area is found by computing the product of the base and the height. Can your daughter identify the measures of the base and height?
 
Re: Solving how many square inches with in a flag

MarkFL said:
The white stripe is a parallelogram, whose area is found by computing the product of the base and the height. Can your daughter identify the measures of the base and height?

Yeah I think you are right. I'm just going with the 72 x 8.5. thanks for you input.
 
Re: Solving how many square inches with in a flag

wtam1100 said:
Yeah I think you are right. I'm just going with the 72 x 8.5. thanks for you input.

Yes, that's correct! (Star)
 
Hi,
I think a diagram is helpful:

3466x7a.png
 
the white area is essentially a parallelogram
to calculate the area of a parallelogram

A = base x height

A = 8.5 x 72 = 612 square inches
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Replies
1
Views
2K
Replies
8
Views
3K
Replies
4
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
2
Views
2K
Replies
1
Views
1K
Replies
7
Views
3K
Back
Top