Solving Infinite Sums/Series: Kid Tutoring Homework

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The discussion revolves around solving the infinite series S = 1 + 3x + 5x^2 + ... for a student. The user attempts to express the series in terms of a summation formula, identifying the nth term as tn = (2n-1)x^(n-1). They derive a partial sum but struggle with the integration needed to simplify it further, noting that the student has not yet learned integration. A hint suggests using differentiation instead, leading to the conclusion that the sum could be expressed as (1+x)/(1-x)^2. The user expresses some frustration but ultimately seeks to provide a clear answer to the student.
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Homework Statement


Figuring out an infinite sum question for the kid I tutor... it's late and my brain's not functioning well. I think I'm overcomplicating the question, but I can't figure it out.

The the sum of the following infinite series:
S = 1+3x+5x^2+...

Homework Equations



The Attempt at a Solution


I got that tn = (2n-1)x^{n-1}

Which means the sum is
\Sigma (2n-1)x^{n-1}=2\Sigma nx^{n-1} - \Sigma x^{n-1} = 2\Sigma nx^{n-1} - \frac{1}{1-x}

And here is where I get stuck...
 
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Hi muso07! :smile:

Hint (for ∑ nxn-1):

integrate. :wink:
 
Hm, the kid's in Year 11 so he hasn't done integration yet...

But when you integrate, you get x^n. Then lim_{(a\rightarrow\infty)} [x^{n}]^{a}_{1}= lim_{(a\rightarrow\infty)}x^{a}-x=-x
This isn't right, though... I feel like such an idiot. :P
 
(have a sigma: ∑ and an infinity: ∞ and try using the X2 and X2 tags just above the Reply box :wink:)

No, you want d/dx lima->∞ (∑xn) :smile:
 
You beat me to replying. Is the sum (1+x)/(1-x)^2?
 
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Nevermind, I'm just going to tell him to believe me and it shall be great.

Thanks for all your help!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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