Solving Initial Value Problems for Second Order Differential Equations

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SUMMARY

This discussion focuses on solving initial value problems (IVPs) for second-order differential equations. The first equation, y'' + y = 0, has solutions cos(x) and sin(x), leading to the conditions y(x0) = 1 and y'(x0) = 0. The second equation, y'' - λ²y = 0, has solutions e^(λx) and e^(-λx), with initial conditions y(x0) = 0 and y'(x0) = 1. The participants confirm that solving for the constants C1 and C2 is necessary to fully determine the solutions.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with initial value problems (IVPs)
  • Knowledge of trigonometric functions and their derivatives
  • Basic concepts of exponential functions and their properties
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  • Study methods for solving second-order linear differential equations
  • Learn about the application of initial conditions in differential equations
  • Explore the role of characteristic equations in determining solutions
  • Investigate the use of Laplace transforms for solving IVPs
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Students and educators in mathematics, particularly those focusing on differential equations, as well as anyone looking to deepen their understanding of initial value problems and their solutions.

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Homework Statement



Solve the following IVPs.

a) y'' + y = 0 for y(x0)=1 and y'(x0)=0

b) y'' - λ2y = 0 for y(x0)=0 and y'(x0)=1

Homework Equations


The Attempt at a Solution



a) Two distinct solutions for y'' + y = 0 are cos(x) and sin(x).

So, y(x0) = C1cos(x0) + C2sin(x0) = 1

y'(x0) = -C1sin(x0) + C2cos(x0) = 0

b) Two distinct solutions for y'' + λ2y = 0 is just e^([tex]\lambda[/tex]x) and e^(-[tex]\lambda[/tex]x)

So,

y(x0) = C1e^([tex]\lambda[/tex]x0) + C2e^([tex]\lambda[/tex]x0)) = 0

y'(x0) = C1λe^([tex]\lambda[/tex]x0) - C2λe^(-[tex]\lambda[/tex]x0) = 1

Now do I need to go through and solve for the C's or I am OK?
 
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tracedinair said:
Now do I need to go through and solve for the C's … ?

Yup! :biggrin:
 
tiny-tim said:
Yup! :biggrin:

Thank you, my notes weren't very clear on the next step.
 

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