Using the approximation, explain why the second derivative test works.

[jumboopizza]

1. Homework Statement [/
Using the approximation, explain why the second derivative test works

approximation=f(x0+delta x, y0+delta y)

delta x and delta y are small...

Homework Equations

f(x0+delta x,y0+delta y)

The Attempt at a Solution

ok so i know the first derivative of it is:

fx(x0+y0)*delta x+fy(x0+y0)*delta y

and second derivative is:

fxx(x0,y0)*delta x^2+fxy(x0,y0)*delta x*delta y+fyy(x0,y0)*delta y^2

it justs seems like since delta x and delta y are getting smaller,that everything will be going towards 0...so why does it work?

 

[SammyS]

What is the problem as written?

f appears to be a function of two variables. What is the second derivative test for a function of two variables?

 

[jumboopizza]

Using the approximation, explain why the second derivative works. Give three exam-
ples for each scenario of the second derivative test.

isnt that what the approximation is? the f(x+delta x,y +delta y)?

its asking about finding local mins,local max and saddle points...now i can show those examples,but how can i explain how it works?its like a proof or something

 

[Ray Vickson]

1. Homework Statement [/
Using the approximation, explain why the second derivative test works

approximation=f(x0+delta x, y0+delta y)

delta x and delta y are small...

Homework Equations

f(x0+delta x,y0+delta y)

The Attempt at a Solution

ok so i know the first derivative of it is:

fx(x0+y0)*delta x+fy(x0+y0)*delta y

and second derivative is:

fxx(x0,y0)*delta x^2+fxy(x0,y0)*delta x*delta y+fyy(x0,y0)*delta y^2

it justs seems like since delta x and delta y are getting smaller,that everything will be going towards 0...so why does it work?

Homework Statement

Homework Equations

The Attempt at a Solution

You don't say what you are testing for. If you mean the second-order test for a maximum or minimum, you still need to be more specific: the necessary conditions and the (most common) sufficient conditions are a bit different. You need to tell us which ones you want.

RGV

 

[SammyS]

Mathematical language is very exacting. You need to say what you mean & mean what you say.

f(x₀+Δx, y₀+Δy) is the (exact) value of the function, f, at the point (x₀+Δx, y₀+Δy).

If the first derivatives of f are zero at the point, (x₀, y₀), then the following is an approximation to f at the point (x₀+Δx, y₀+Δy).

f(x₀+Δx, y₀+Δy) ≈ f(x₀, y₀) + (1/2)[ f_xx(x₀, y₀)(Δx)² +2 f_xy(x₀, y₀)(Δx)(Δy) + f_yy(x₀, y₀)(Δy)² ]