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Solving kinetic energy of reaction's products

  1. Dec 10, 2014 #1
    1. The problem statement, all variables and given/known data

    This is my first thread in this forum, please forgive me if I made any mistake on posting.




    2. Relevant equations

    I am having difficulty on solving the Problem 5.


    3. The attempt at a solution

    The answer I obtained is 1.5MeV, is it correct ?
     

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  2. jcsd
  3. Dec 12, 2014 #2
    i think its 2.5MeV
    the mass defect of X is 2MeV since the K.E. released(energy of the products) must be equal to the mass defect.
    in 2nd eqn, the mass defect is sum of Mass defect of X and the electron
    therefore we add 0.5MeV to the X's 2.0MeV to get 2.5MeV


    proton007007
     
  4. Dec 12, 2014 #3

    BvU

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    Hello Ryan, welcome to PF :)
    Just so you learn from your 'mistakes': "I am having difficulty on solving the Problem 5" does not count as a relevant equation. Neither does " The answer I obtained is 1.5MeV, is it correct ? " count as an attempt at solution. PF has this template for very good reasons (see guidelines). We're not here to stamp-approve homework, but to help people along. So we need to know where you are and you can show by properly formulating the problem (i.e. not linking to a rotated test page) and listing off variables & known/given data, line up the equations you think you need and show what you have done.

    I also have a question for proton: in the sescond reaction you also don't have to create a positron. Doesn't that yield another .5 MeV ?
     
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