Deriving hamiltonian operator for rotational kinetic energy.

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SUMMARY

The discussion focuses on deriving the Hamiltonian operator for a rigid rotor, specifically addressing the rotational kinetic energy equation. The key equation presented is K = (1/2)Iω², where I represents the moment of inertia and ω is the angular velocity. The relationship between angular momentum (L) and kinetic energy is established as K = L²/(2I). This derivation is rooted in classical mechanics principles and aims to clarify the Hamiltonian formulation for rotational systems.

PREREQUISITES
  • Understanding of Hamiltonian mechanics
  • Familiarity with rotational dynamics
  • Knowledge of angular momentum concepts
  • Basic algebra and calculus skills
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  • Study Hamiltonian mechanics in detail
  • Explore the derivation of moment of inertia for various shapes
  • Learn about the relationship between angular momentum and rotational kinetic energy
  • Investigate applications of Hamiltonian operators in quantum mechanics
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Students and professionals in physics, particularly those studying classical mechanics and quantum mechanics, as well as anyone interested in the mathematical formulation of rotational systems.

georg gill
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Homework Statement



I am trying to get the hamiltonain operator equality for a rigid rotor. But I don't get it. Please see the red text in the bottom for my direct problem. The rest is just the derivation I used from classical mechanics.

Homework Equations



upload_2016-1-16_8-57-32.png


By using algebra we obtain:

upload_2016-1-16_8-58-19.png


By using this definition K of rotational kinetic energy one writes:
upload_2016-1-16_8-59-51.png


The Attempt at a Solution



upload_2016-1-16_9-0-25.png
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You can show that
$$K = \frac 12 \mu (r\omega)^2 = \frac 12 (\mu r^2)\omega^2 = \frac 12 I \omega^2 = \frac{L^2}{2I},$$ where ##L## is the angular momentum of the system.
 

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