Solving Legendre's Equation | Recurrence Relation

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Homework Statement



Obtain the recurrene relation between the coefficient ar in the series solution

y= (between r=0 and \infty) \Sigma arxr

to (1-x2)y''-2xy'+k(k+1)y=0
Deduce that if k is a positive integer, then ak+2=0, so that the equation possesses a solution which is a polynomial of degree k.

Homework Equations



(there is more to this question...but i think ill try getting through this bit first!)


The Attempt at a Solution



I have managed to get the correct recurrance relation

(n+2)(n+1)an+2-an(n(n+1)-k(k+1))=0

But i have no idea what to do now (the show if k is a positive integer) etc :-(
 
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So
a_{n+2}= a_n\frac{n(n+1)- k(k+1)}{(n+1)(n+2)}
Assume that a0 and a1[/sup] are given. What is a2, a3, a4 in terms of a0 and a1. Can you guess a form for the general an form? Can you then prove it by, say, induction?
 
i am not too sure what induction is...(sorry!) guessing a form for an - do you is this not given by the recurrance relation?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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