Solving Line Integral Problem on Curve z=x+y with Simple Parametric Equations

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SUMMARY

The discussion focuses on evaluating the line integral \(\int_{C}x^{2}yz\,ds\) along the curve defined by \(z = x + y\) and the plane equation \(x + y + z = 1\). The correct evaluation yields \(\frac{37\sqrt{2}}{3}\), which was derived using specific parametric equations and bounds. A participant identified a miscalculation in the distance formula, specifically noting that \(\sqrt{(1)^{2}+(-1)^{2}} \neq 1\), indicating a need for accurate parameterization and bounds in the solution process.

PREREQUISITES
  • Understanding of line integrals in multivariable calculus
  • Familiarity with parametric equations and their applications
  • Knowledge of the distance formula in three-dimensional space
  • Ability to manipulate and solve equations involving multiple variables
NEXT STEPS
  • Review the concept of line integrals in multivariable calculus
  • Study parametric equations and their role in curve representation
  • Learn about the distance formula in three-dimensional geometry
  • Practice solving similar line integral problems with varying bounds
USEFUL FOR

Students and educators in calculus, particularly those focusing on line integrals and parametric equations, as well as anyone seeking to improve their problem-solving skills in multivariable calculus.

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Homework Statement



Evaluate the line integral,

\int_{C}x^{2}yzds, \text{ where C is the curve } z = x + y, \quad x + y + z = 1\text{ from }(1,\frac{-1}{2},\frac{1}{2}) \text{ to } (-3, \frac{7}{2}, \frac{1}{2})

Homework Equations





The Attempt at a Solution



Here's my attempt at the problem,

attachment.php?attachmentid=31302&stc=1&d=1294959785.jpg


It lists the correct answer as, \frac{37\sqrt{2}}{3} solved with different parametric equations and bounds for t as well.

What am I doing wrong?
 

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I see one problem right away:
\sqrt{(1)^{2}+(-1)^{2}} \ne 1
 

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