Solving Linear Equations d= Lh/R1+R2 for L

[Rose Bernard]

How do i solve d= Lh/R1+R2.
How do i also solve d= LM/R2+R1.

 

[MarkFL]

How do i solve d= Lh/R1+R2.
How do i also solve d= LM/R2+R1.

Hello, and welcome to MHB! (Wave)

Let me first ask if the equations are:

1.) $$d=\frac{Lh}{R_1+R_2}$$

2.) $$d=\frac{LM}{R_1+R_2}$$

If so, which variable are you being asked to solve for in each equation?

 

[Rose Bernard]

Solve for L:
d=Lh/R1+R2

Also solve d= LM/R2+R1.

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They are two different questions.

 

[MarkFL]

Yes, I made my best attempt to decide what your somewhat ambiguous notation means...I posted both equations, and I am waiting for you to confirm whether I have interpreted them correctly and for which variable each are to solved. (Smile)

 

[Rose Bernard]

Yes,those are the equations.
Are you there?

 

[MarkFL]

Yes,those are the equations.
Are you there?

Yes...this isn't like instant messaging. Sometimes a reply might take more than a few minutes, as I am also doing many other things. :)

So, the first equation is:

$$d=\frac{Lh}{R_1+R_2}$$

And we are to solve for $L$.

The first thing I would do is multiply both sides by $R_1+R_2$ to clear the denominator on the RHS. What do we get in doing so?

 

[Rose Bernard]

Again this are the questions:

Solve for L: d=Lh/R1+R2. This is the first question.

Second question:
d= LM/R2+R1.

Thank you.

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I really don't know how to solve it,so please just help me out. Help me by solving and telling me the answer,and i will learn it.

 

[MarkFL]

I am offering guidance, so that you are involved in the process of solving...you'll learn more that way. So, if we multiply as I suggested, we get:

$$d\left(R_1+R_2\right)=\frac{Lh}{R_1+R_2}\left(R_1+R_2\right)$$

What do you have when you cancel or divide out common factors on the RHS?

 

[Rose Bernard]

Please no idea.
Tell me

 

[topsquark]

Please no idea.
Tell me

C'mon. [math]\frac{a}{a} = 1[/math] for all [math]a \neq 0[/math].

So what is [math]\frac{R_1 + R_2}{R_1 + R_2}[/math]?

-Dan

 

[Rose Bernard]

C'mon. [math]\frac{a}{a} = 1[/math] for all [math]a \neq 0[/math].

So what is [math]\frac{R_1 + R_2}{R_1 + R_2}[/math]?

-Dan

R1+R2=R3.
If am not mistaking.

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C'mon. [math]\frac{a}{a} = 1[/math] for all [math]a \neq 0[/math].

So what is [math]\frac{R_1 + R_2}{R_1 + R_2}[/math]?

-Dan

Are you there

 

[topsquark]

R1+R2=R3.
If am not mistaking.

Let's try again with numbers. Set [math]R_1 + R_2 = R_3 = 10[/math]. Then
[math]\frac{R_1 + R_2}{R_1 + R_2} = \frac{R_3}{R_3} = \frac{10}{10} = [/math]?

-Dan

 

[Rose Bernard]

C'mon. [math]\frac{a}{a} = 1[/math] for all [math]a \neq 0[/math].

So what is [math]\frac{R_1 + R_2}{R_1 + R_2}[/math]?

-Dan

Please i don't know

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Please i don't know

Maybe R3/R3

 

[Rose Bernard]

Hello
Please we didn't complete our business yesterday.

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Please help me solve: d= LM/R2+R1.
And also help me solve: solve for L: d=Lh/R1+R2.

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Hello MarkFL
Please we didn't finish our business yesterday.
If you don't mind can we continue?

 

[MarkFL]

Hello
Please we didn't complete our business yesterday.

I left it at:

$$d\left(R_1+R_2\right)=\frac{Lh}{R_1+R_2}\left(R_1+R_2\right)$$

Cancelling on the RHS leaves:

$$d\left(R_1+R_2\right)=\frac{Lh}{\cancel{R_1+R_2}}\left(\cancel{R_1+R_2}\right)$$

$$d\left(R_1+R_2\right)=Lh$$

Now, since $L$ is being multipled by $h$, we want to divide both sides by $h$...what do we get?

 

[Wilmer]

Rose, are you a student attending math classes?