Solving Long Jump Question: Find Takeoff Speed

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To solve for the takeoff speed of a runner who jumps at a 30-degree angle and covers 8.90 meters, the velocity must be resolved into horizontal and vertical components. The horizontal component remains constant due to no acceleration, while the vertical component is influenced by gravity. Key equations involve using the angle to determine these components, specifically vcosθ for horizontal and vsinθ for vertical motion. The time of flight and maximum height are crucial for finding the initial velocity, with the final vertical velocity being zero at the peak height. Understanding and applying kinematic equations is essential to progress in solving the problem.
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Homework Statement



A runner jumps at 30 degrees to the ground and covers 8.90 m. What was the takeoff speed?


The Attempt at a Solution



I have no idea where to start...
 
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Resolve the velocity into vertical and horizontal components.
What happens to these components with respect to time?
 
how would i go about solving the velocity for each component?
 
If v is the velocity what are the vertical and horizontal components?
 
honestly, i have no idea
 
Open any textbook. And refer the motion in two dimension.
 
but all i have is the angle of the jump and the distance...no time or anything
 
Using proper equation you can find the remaining unknown quantities. Try to find out the equations.
 
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
 
  • #10
honestly, I am struggling and have no idea what to do...
 
  • #11
SirMarksAlot said:
do u mean these formulas?

Fx = cos A * F1
Fy = sin A * F1
Yes. These are the two components. Only replace F by v for the velocity.
In that x component remains constant, because there is no acceleration in that direction. If t is the time of flight, then x = vcosθ*t.
In the vertical direction, the initial velocity is vsinθ. What is the final velocity when it reaches the maximum height. And what is the time taken to reach the maximum height?
 
  • #12
when u say x = vcosθ*t , what is v? the speed before the jump?
 
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  • #13
No. You have to find out. I have told you to write down all the kinematic equations. Then I will tell you which equation to be used to find the time.
 
  • #14
oh wouldn't the final velocity be 0 when it reaches a maximum height? because he would have stopped moving up?
 
  • #15
Yes.
 
  • #16
I don't know how to find the time it would take to reach the max height.
 
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  • #17
Why can't you write down all the relevant kinematic equation. In the post submitted to PF, this is the second requirement.. You have not submitted that. Do it first now.
 

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