Solving Manometer Problems - Pressure at Point B

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The discussion revolves around calculating the pressure at point B in a manometer, given specific heights and densities. The user is using the equation P1-P2=pg(h2-h1) but is uncertain about the role of the density values provided, particularly p(roh)m, which is identified as the density of mercury. Participants clarify that the density of 13784 kg/m^3 is indeed mercury, while the 882 kg/m^3 could represent ethanol, suggesting a potential mix of liquids in the manometer. There is confusion regarding the notation used for density and the type of manometer being analyzed. Overall, the thread seeks clarity on the calculations and the properties of the fluids involved.
adam112
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Hi all, I really need some help with the following question,

I have to find the pressure at point B, within the manometer.
height A=0.71m
height B=200mm
p(roh)=882 kg/m^3
p(roh)m=13784 kg/m^3 (is this the density of the gas?)
Pressure at point A=156850Pa

I have tried using the following equation: P1-P2=pg(h2-h1), is this correct?

The answer I am getting is 18196.73 Pa, but I am not including p(roh)m in the equation.

I hope what I am trying to ask makes sense.

If anybody can help, and maybe push me in the direction of a few websites, it would be mostly appreciated.
 
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adam112 said:
Hi all, I really need some help with the following question,

I have to find the pressure at point B, within the manometer.
height A=0.71m
height B=200mm
p(roh)=882 kg/m^3
p(roh)m=13784 kg/m^3 (is this the density of the gas?)
Not unless you think a cubic meter of the gas weighs about 14 metric tons! Sounds more like mercury ('m' = mercury?) to me...
I'm having trouble with the 'roh' part of p(roh).
 
what kind of manometer is that?is it a differential type? you mean the specific density p(roh)m? what element is p1 and p2? are they both h20?
 
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chemisttree said:
I'm having trouble with the 'roh' part of p(roh).
I'm guessing that, in the original problem, it's just a rho, and adam112 used a p because it looks like a rho, then put rho in parens to clarify (achieving, unfortunately, the opposite).

adam112: Do you have a picture?

13784 kg/m^3 is definitely the density of mercury, as chemisttree suggests. I'm not sure what the 882 kg/m^3. It would be about right for, say, ethanol, and is way too high for a gas. (And usually in a problem of this type the density of any gases would be negligible.) But without more info, I don't know why there would be two liquids involved.
 
Just FYI, this thread is 3 years old.
 
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