Solving Natural Logarithms

  • #1

Homework Statement

Solve for x


My attempt at the solution

I first moved "-24" and "-4x" to the right side of the equation yielding


I then converted the natural logarithms to exponent form and product form yielding

ln(x)^x+ln(x)^6 = 24+4x ====> ln(x^x*x^6)=24+4x =====> ln(x^(x+6))=24+4x

I then converted the equation in notation " e " form yielding

e^(24+4x)= x^(x+6)

Now I am stuck on where to proceed. I am aware that the answer has to be a positive number because the domain of a logarithm is always greater then 0.

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  • #2
That is not going to have a solution in terms of any simple algebraic function. It might have a solution in terms of the "W" function which is defined as the inverse function to [itex]f(x)= xe^x[/itex].
  • #3
You were on the right track when you collected like terms:

If you factor the LHS further, notice:
ln(x) (x+6)=24+4x

Can you figure out what x must be now? (Sorry, Mr. Lambert. No soup for you today.)

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