Solving Nuclear Fission Reactions & Calculating Energy Released

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SUMMARY

The discussion focuses on solving nuclear fission reactions, specifically the fission of uranium-235 (U-235) when it interacts with a neutron. The reaction produces germanium-81 (Ge-81), five additional neutrons, and another unidentified element. The atomic number and mass of this element can be determined by balancing the atomic numbers and masses before and after the reaction. Additionally, the energy released from the complete fission of one kilogram of U-235 oxide is calculated using the energy per atom, which is 3.2 x 10^-11 joules.

PREREQUISITES
  • Understanding of nuclear fission reactions
  • Knowledge of atomic number (Z) and atomic mass (A)
  • Familiarity with neutron and proton balance in nuclear equations
  • Ability to use charts of nuclides for radionuclide mass
NEXT STEPS
  • Learn how to balance nuclear equations involving fission reactions
  • Study the properties of germanium isotopes and their formation
  • Explore energy calculations in nuclear reactions, focusing on U-235
  • Investigate resources for accessing charts of nuclides and their applications
USEFUL FOR

Students in nuclear physics, educators teaching fission concepts, and anyone interested in understanding the energy dynamics of nuclear reactions.

david1362
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hi guys, iam kinda stuck on 2 problems. here is what it is :

The nuclear fission reaction of uranium-235 with one neutron produces germanium-81, 5 neutrons and another element, what element is that? what's the atomic number andatmoic mass,?give the equation.





2. how much energy is released in the complete fission of one kg of U-235 oxide? given that energy fission of one atom of uranium is 3.2 x 10^-11 J


Thanks guys
 
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show work done. what have you tried?
 
i mentioned i was stuck

the thing u just said in ur reply won't help at all, how would u like me to give u such an answer to ya? you would have been better not replying
 
The rules of these forums is that you show work done and that you have attempted a solution. If you have not read the rules, then i suggest you do it.

https://www.physicsforums.com/showthread.php?t=5374

read "homework help"


Use the template, and if Som eone replied to me in that manner i did to you, i would admit that i have done a misstake and would try to come up with an attempt to a solution.

I can give you a hint, count the number of neutrons and protons before and after the reaction and see what yo u get. (for the first problem)
 
Last edited:
david1362 said:
the thing u just said in ur reply won't help at all, how would u like me to give u such an answer to ya? you would have been better not replying
We respectfully request that students show work and effort in solving the HW problems when asking for assistance, as malawi_glenn appropriately indicated.

http://www.webelements.com/

We know the start U (Z=92, A=235) + 1 n -> Ge(Z=?, A=81) + ? + 5n.

Determine the change in Z and the balance the neutrons. In a nucleus of an isotope, the number of neutrons N = A - Z, where A is the atomic mass and Z is the atomic number.

One has to go to a chart of nuclides for the actual mass of a particular radionuclide.

http://www.nndc.bnl.gov/chart/ - click on a location in the chart, the use zoom 1, upper right, in order to see details.
 
Astronuc said:
We respectfully request that students show work and effort in solving the HW problems when asking for assistance, as malawi_glenn appropriately indicated.

http://www.webelements.com/

We know the start U (Z=92, A=235) + 1 n -> Ge(Z=?, A=81) + ? + 5n.

Determine the change in Z and the balance the neutrons. In a nucleus of an isotope, the number of neutrons N = A - Z, where A is the atomic mass and Z is the atomic number.

One has to go to a chart of nuclides for the actual mass of a particular radionuclide.

http://www.nndc.bnl.gov/chart/ - click on a location in the chart, the use zoom 1, upper right, in order to see details.


Thanks a lot, i appreciate it, sorry i lose temper, but iam under so much pressure in this class. thanks again, I hope i can help you with your questions soon.
 

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