Solving Nuclear Fission Reactions & Calculating Energy Released

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Homework Help Overview

The discussion revolves around nuclear fission reactions, specifically involving uranium-235 and the products of its fission, including germanium-81 and additional neutrons. Participants are also exploring the calculation of energy released during the fission of one kilogram of U-235 oxide.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the identity of the additional element produced in the fission reaction and its atomic properties. There is also an inquiry into the energy released from the fission of a specific mass of U-235 oxide.

Discussion Status

The conversation includes requests for participants to show their work and previous attempts at solving the problems. Some participants have provided hints regarding balancing neutrons and protons in the reaction, as well as referencing external resources for further information.

Contextual Notes

There is a noted emphasis on following forum rules regarding showing work and effort in homework inquiries. Participants express varying levels of frustration regarding the responses received and the pressure of the coursework.

david1362
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hi guys, iam kinda stuck on 2 problems. here is what it is :

The nuclear fission reaction of uranium-235 with one neutron produces germanium-81, 5 neutrons and another element, what element is that? what's the atomic number andatmoic mass,?give the equation.





2. how much energy is released in the complete fission of one kg of U-235 oxide? given that energy fission of one atom of uranium is 3.2 x 10^-11 J


Thanks guys
 
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show work done. what have you tried?
 
i mentioned i was stuck

the thing u just said in ur reply won't help at all, how would u like me to give u such an answer to ya? you would have been better not replying
 
The rules of these forums is that you show work done and that you have attempted a solution. If you have not read the rules, then i suggest you do it.

https://www.physicsforums.com/showthread.php?t=5374

read "homework help"


Use the template, and if Som eone replied to me in that manner i did to you, i would admit that i have done a misstake and would try to come up with an attempt to a solution.

I can give you a hint, count the number of neutrons and protons before and after the reaction and see what yo u get. (for the first problem)
 
Last edited:
david1362 said:
the thing u just said in ur reply won't help at all, how would u like me to give u such an answer to ya? you would have been better not replying
We respectfully request that students show work and effort in solving the HW problems when asking for assistance, as malawi_glenn appropriately indicated.

http://www.webelements.com/

We know the start U (Z=92, A=235) + 1 n -> Ge(Z=?, A=81) + ? + 5n.

Determine the change in Z and the balance the neutrons. In a nucleus of an isotope, the number of neutrons N = A - Z, where A is the atomic mass and Z is the atomic number.

One has to go to a chart of nuclides for the actual mass of a particular radionuclide.

http://www.nndc.bnl.gov/chart/ - click on a location in the chart, the use zoom 1, upper right, in order to see details.
 
Astronuc said:
We respectfully request that students show work and effort in solving the HW problems when asking for assistance, as malawi_glenn appropriately indicated.

http://www.webelements.com/

We know the start U (Z=92, A=235) + 1 n -> Ge(Z=?, A=81) + ? + 5n.

Determine the change in Z and the balance the neutrons. In a nucleus of an isotope, the number of neutrons N = A - Z, where A is the atomic mass and Z is the atomic number.

One has to go to a chart of nuclides for the actual mass of a particular radionuclide.

http://www.nndc.bnl.gov/chart/ - click on a location in the chart, the use zoom 1, upper right, in order to see details.


Thanks a lot, i appreciate it, sorry i lose temper, but iam under so much pressure in this class. thanks again, I hope i can help you with your questions soon.
 

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