Solving Oscillating Mass Displacement Problem: Max Velocity Calc

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SUMMARY

The discussion focuses on calculating the maximum velocity of a mass suspended from a spring, specifically a 0.3 kg mass with a spring stiffness of 200 N/m. The problem involves displacing the mass by 10 mm from its equilibrium position and applying Hooke's Law (F = kx) to determine the amplitude of oscillation. Participants emphasize using conservation of energy principles to relate the potential energy stored in the spring to the kinetic energy at maximum velocity, clarifying that oscillations occur around the equilibrium position rather than the unstretched length of the spring.

PREREQUISITES
  • Understanding of Hooke's Law (F = kx)
  • Basic principles of conservation of energy
  • Knowledge of oscillatory motion and equilibrium positions
  • Familiarity with gravitational force calculations (F = mg)
NEXT STEPS
  • Study the application of conservation of energy in oscillatory systems
  • Learn about the dynamics of simple harmonic motion (SHM)
  • Explore the relationship between spring constant and oscillation frequency
  • Investigate the effects of damping on oscillatory motion
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Students in physics or engineering, particularly those studying mechanics and oscillatory systems, as well as educators looking for examples of practical applications of Hooke's Law and energy conservation.

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i know this problem is posted on this forum somwhere else but i can't quite understand thanks in advance

Homework Statement



A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If
the mass is displaced by 10 mm from its equilibrium position and
released, for the resulting vibration, calculate:

the maximum velocity of the mass during the vibration

Homework Equations



F=kl



The Attempt at a Solution



so far i am thinking that i need to use hookes law as follows so i can get the amplitude
F=k(l+x)

F= mg = 0.3 kg x 9.81 = 2.94 N
k = 200 Nm-1
l = static spring reflection = 2.94/200 = 0.01
x = displacement due to external force = 10mm

so the amplitude would be l + x = 10.01mm?

do i need to take into account the extra extension when attempting the solution or is it just f/k =l
or do i need to use f/k = l + x to calculate the amplitude


any help would be appriciated

Thanks
 
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The oscillations are around the equilibrium position, not the unstretched length.
Remember you have gravity as well as the string acting on the mass.

I would use conservation of energy for this problem.
For instance, at the top of the motion, the energy stored in the spring has been changed into gravitational potential energy.
 

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