1. The problem statement, all variables and given/known data The mass m = 4 kg and the spring constant k = 64 N/m. The spring is unstretched when x = 0. At t = 0, x = 0 and the mass has a velocity of 2 m/s down the inclined surface. What is the value of x at t = 0.8 s? The angle of incline is 20 degrees, and with the mass moving down to the right with a spring attached on its left surface. 2. Relevant equations ΣFx = max x = Asin(wt)+Bcos(wt) 3. The attempt at a solution d2x/dt2 + (16 s-2)x = 3.355 m/s2 I got to this point and I found that for the equation x = Asin(wt)+Bcos(wt) the solution gives x = Asin(wt)+Bcos(wt) + 0.210 m. I get that 0.210 = 3.355/16, but why is it included in this solution for the equation when all other examples of this problem for a vertically or horizontally held spring mass system use just the x = Asin(wt)+Bcos(wt) equation without this addition value? What is this value, and is it just disregarded as zero in the other forms of this problem?