Solving Part B: Acceleration of End B after String Cut

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SUMMARY

The discussion focuses on calculating the initial acceleration of end B of a rod when the supporting string is cut. The rod has a length of 69.0 cm and a mass of 1.70 kg. When the string on side B is cut, the initial acceleration is determined using the formula Fg = mg, resulting in an acceleration of 9.8 m/s². The problem also involves a scenario where the string on side B is retied to half the length of the string on side A, which requires further analysis to find the new acceleration.

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Homework Statement



A rod of length 69.0 cm and mass 1.70 kg is suspended by two strings which are 43.0 cm long, one at each end of the rod.

http://schubert.tmcc.edu/res/msu/physicslib/msuphysicslib/20_Rot2_E_Trq_Accel/graphics/prob13a_1016full.gif

(A) The string on side B is cut. Find the magnitude of the initial acceleration of end B.

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The string on side B is retied and now has only half the length of the string on side A.

http://schubert.tmcc.edu/res/msu/physicslib/msuphysicslib/20_Rot2_E_Trq_Accel/graphics/prob13b_1016half.gif

(B) Find the magnitude of the initial acceleration of the end B when the string is cut.

Homework Equations





The Attempt at a Solution



A bit lost on even how to solve this one. Any assistance would be appreciated. Thanks.
 
Last edited by a moderator:
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Assuming no air resistance
Fg = (m)(g)
Fg = (1.70kg)(9.8m/s^2)
Fg = 16.6

a = Fnet/m
a = 16.6/1.70
a = 9.8 m/s^2

Think that's right...?
 

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