Solving Percentages: Remove 9% and Keep Total at 100%

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To remove 9% from a set of percentages while keeping the total at 100%, convert the percentages to decimal fractions. The original percentages of 24.57%, 44.59%, 3.64%, and 18.20% can be expressed as 0.2457, 0.4459, 0.0364, and 0.1820. By dividing each of these decimal values by 0.91, the resulting numbers will proportionally adjust to maintain a total of 1.0. This method ensures that the remaining percentages absorb the removed 9% without equal distribution. The approach effectively recalibrates the values while preserving their relative proportions.
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Hi all,

I'm a complete math idiot and was wondering if somebody could help me out with an equation that I'm trying to solve.

Lets say I have the following percentages that equal 100%

24.57%
44.59%
3.64%
18.20%
9%

Now let's say I want to remove the 9% but I want the remaining 4 numbers to still equal 100%. How would I distribute the 9% difference? I should also add, I don't want to divide the 9% by 4 and then equal distribute that among the numbers I want them to absorb according to their current percentage. If that makes any sense at all.

Thanks
-Brandon
 
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brandozz said:
Hi all,

I'm a complete math idiot and was wondering if somebody could help me out with an equation that I'm trying to solve.

Lets say I have the following percentages that equal 100%

24.57%
44.59%
3.64%
18.20%
9%

Now let's say I want to remove the 9% but I want the remaining 4 numbers to still equal 100%. How would I distribute the 9% difference? I should also add, I don't want to divide the 9% by 4 and then equal distribute that among the numbers I want them to absorb according to their current percentage. If that makes any sense at all.

Thanks
-Brandon

First off, it's probably simpler to convert all of your numbers to decimal fractions, and get rid of the %. This makes your first four numbers
.2457
.4459
.0364
.1820

Now divide each of these numbers by .91, which will give you a new set of numbers that will add to 1.0. All of the numbers will be proportionally larger than what you started with.
 
Thanks

Thanks for you help on this!
 
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