# Solving Physics Homework: Question Redirected

• Void123
In summary, the conversation is discussing the use of spherical coordinates and boundary conditions in finding the potential for a conducting sphere. It is mentioned that without boundary conditions, the potential cannot be determined. The solution will satisfy a Laplace equation and may have multiple possible solutions depending on the specified boundary conditions. A reference for further understanding is also provided.
You use spherical coordinates, but without boundary conditions, you will not be able to find the potential, so you need to specify them.

Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.

So, my solution will satisfy:

$$\nabla^{2}\Psi = 0$$

$$\Psi = \sum a \Psi$$

Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?

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