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Void123

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## Homework Statement

https://www.physicsforums.com/showthread.php?p=2484733&posted=1#post2484733

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- Thread starter Void123
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In summary, the conversation is discussing the use of spherical coordinates and boundary conditions in finding the potential for a conducting sphere. It is mentioned that without boundary conditions, the potential cannot be determined. The solution will satisfy a Laplace equation and may have multiple possible solutions depending on the specified boundary conditions. A reference for further understanding is also provided.

- #1

Void123

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https://www.physicsforums.com/showthread.php?p=2484733&posted=1#post2484733

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- #2

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Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.

- #3

Void123

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[tex]\nabla^{2}\Psi = 0[/tex]

[tex]\Psi = \sum a \Psi[/tex]

Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?

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http://www.luc.edu/faculty/dslavsk/courses/phys301/classnotes/laplacesequation.pdf

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