Solving Polynomials - Answers to Common Questions

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To solve the polynomial equation x^5 + ax^3 + bx^2 - 3 = (x^2 - 1)Q(x) - x - 2, substitute x = 1 and x = -1 to eliminate Q(x) and create two equations involving a and b. This approach allows for simultaneous solving of the equations to find the values of a and b. A similar method can be applied to the second equation, 4x^3 + 5x - 2 = (x + 2)(x - 1)P(x) + ax + b, by choosing specific values of x that simplify the equation and eliminate P(x). The key is to strategically select x values that make certain terms zero, facilitating the solution process. Understanding these techniques is crucial for solving polynomial equations effectively.
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i'm pretty new to polynomials and I have qns, which I do not know how to solve.

x5 + ax3 + bx2 - 3 = (x2 - 1)Q(x)- x - 2

Q(x) is a polynomial. Solve a and b.

I know the degree of Q(x) is 3, so I subst Q(x) into x3, but I got stuck.

Help. Thanks in advance.
 
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You don't need to know what Q(x) is. The zeroes of x^2-1 are x=\pm 1 so if you substitute x=1 into the entire equality, that Q(x) part cancels since anything times zero is zero (your 'anything' is the Q(x)) and then you'll get an equation in a and b. Then substitute the other value of x to get another equation in a and b. Solve simultaneously and you're done! :smile:
 
Thank you very much.

How about this:

4x3 + 5x - 2 = (x+2)(x-1)P(x) + ax + b

Find a and b. Last qns, I seriously can't solve!
 
If you thought a bit more about what I posted you should have picked up on what to do. What values of x can you choose so that you eliminate the P(x)?
 
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