Solving Principle of Moments: F1 & F2

Click For Summary
SUMMARY

The discussion focuses on solving for forces F1 and F2 using the principle of moments in a static equilibrium problem. The calculations provided indicate that F2 is determined to be 3000N by taking moments about point A, while F1 is calculated to be 2500N by taking moments about point B. However, a participant highlights a misunderstanding in notation and emphasizes the importance of correctly applying the definition of a moment, which is the product of force and distance. The correct approach involves ensuring both force and distance are accounted for in the moment calculations.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of vector notation and trigonometry
  • Familiarity with the concept of moments in physics
  • Ability to perform calculations involving forces and distances
NEXT STEPS
  • Review the definition and applications of moments in physics
  • Practice solving static equilibrium problems using the principle of moments
  • Explore vector notation and its implications in force calculations
  • Learn about the role of trigonometric functions in resolving forces
USEFUL FOR

Students studying physics, engineers working with static systems, and anyone interested in mastering the principles of moments and force calculations in mechanics.

Cain
Messages
1
Reaction score
0
Hello,
This is probably really simple but i don't know if this is the right way to work out the answer
i have attached an image containing the problem.

I know how to get F2 :
Taking moments about A:
F2 Cos 60 = 1500
F2 = 3000N

But then it says to find F1 using the principle of moments, and the only way i can get the answer is:
taking moments about B: (F1 x 1.5) = (1500 x 2.5)
F1 = (1500 x 2.5) / 1.5
F1 = 2500N

is this right?

Thanks a lot
Cain
 

Attachments

  • moments.JPG
    moments.JPG
    4.3 KB · Views: 453
Physics news on Phys.org
Well, you can check your answer by just using trig like you did earlier.
F_1 = F_{2}*cos(30) = 1500*sqrt{3}

You fell into the unfortunate trap of notation. The definition of a moment is that M = B x r, which shows us that the moment is the cross product of the vector and the scalar where the vector is applied. You should go back and nail down the concept of moments, then try the problem out again.
 
Your original equation is not right.

To sum moments, you need a force AND a distance, i.e. F2 (cos 60) * 1.5 = 1500 * 2.5.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
Replies
5
Views
2K
Replies
17
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K