Solving Problem with Units: Max Elastic Potential Energy

  • Thread starter Thread starter jg370
  • Start date Start date
  • Tags Tags
    Units
AI Thread Summary
The discussion focuses on calculating the maximum elastic potential energy of a molecule using a specific equation. The provided equation yields a result of 4.79*10^-12 m, but there is confusion regarding the unit conversions, particularly how to derive meters from Joules and Newtons. Participants analyze the relationships between the units, breaking down the components of Joules and Newtons to clarify the calculations. The conversation highlights the importance of understanding unit dimensions in physics problems. Ultimately, the participants aim to resolve the unit discrepancies to confirm the accuracy of the solution.
jg370
Messages
16
Reaction score
0

Homework Statement


In a problem to determine the maximum elastic potential energy of a molecule, I have the following equation:

A= \sqrt{\frac{6.626*10^-34 Js}{2\pi}}\times(\frac{1}{(1.14*10^-26kg)(1.85*10^3N/m})^(1/4)

Homework Equations




The Attempt at a Solution



The answer is 4.79*10^-12 m

I have tried to coax the definition of the Joule and Newton units to come out with an answer in meter; however I do not see how this can be made to work.

Thank you for your kind assistance

jg370
 
Physics news on Phys.org
(J*s)1/2 = kg1/2*m*s-1/2

(N/m)-1/4 = kg-1/4*m-1/4*s1/2*m1/4

And there hiding in the denominator - the extra kg-1/4

As they say in poker "Pot's right."
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

What is the problem with the units in this state equation of a gas?
Replies
12
Views
2K
Energy in simple harmonic motion--car problem
Replies
4
Views
649
Problem with units? (trying to solve a normalized function)
Replies
9
Views
1K
Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
Replies
44
Views
6K
How Is Electric Potential Difference Calculated in a TV Tube?
Replies
34
Views
2K
Minimizing the Energy of Two Conductors Very Far Apart
Replies
23
Views
1K
Body attached to a block by a spring, shaped like an inclined plane
Replies
1
Views
900
Elastic potential energy - different methods, different results
Replies
2
Views
777
Elastic potential energy problem
Replies
14
Views
4K
How to calculate wavelength electron given speed
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top